Alright, I still kinda have no idea what you just said there, John. What do you mean by "it increasing i by 1 each time"?

128 is only suppose to be a potential for the array, I don't think you keep going regardless of what the user typed in, it's just a "validate the number" checker.



I'm thinking this stuff may still be a bit too advanced for me, I think I'm just going to have to wing the rest of the functions on this assignment, based somewhat off of what Matt already provided for me, as I know I don't have enough time to completely test, compile, and submit the code in time tonight, in addition to fully trying to comprehend why some code works and other attempts don't....

Again though, thanks for all the help guys, I appreciate it.

Originally Posted by jamestl2

Alright, I still kinda have no idea what you just said there, John. What do you mean by "it increasing i by 1 each time"?

Sorry I didn't explain it enough

i is an assumed name of a variable. it can be anything though.
usually when you loop through elements of an array. assuming array name is arr
you need to access its elements like that
arr[0]
arr[1]
arr[2]
etc..
till arr[aSize-1]

where aSize is variable representing the max number can be in the array
say aSize=128 then array elements will be from 0 till 127

it is unreasonable to access it literally like typing
cin>>arr[0]
cin>>arr[1]
till
cin>>arr[127]

so you need to use a loop
with looping usually you loop whenever some condition is true and stop once it's false
you can implement that like the following example code

int i=0;//just a variable called i can be any thing but using i is common
while(i<5)
{
     i++;//increase i by one. the same as i=i+1
     cout<<i<<endl;
}

if you traced that code you will know it runs the command cout<<i
and if you run it it will print like

0
1
2
3
4

in another saying the code above do exactly the same if you used cout to output numbers from 0 to 4

cout<<0<<endl;
cout<<1<<endl;
cout<<2<<endl;
cout<<3<<endl;
cout<<4<<endl;

having that great feature of loop we can input the whole elements of the array from 0th till 127th element a simple loop instead of typing cin 128 times( from 0 till 127)

int i=0;//you need to declare and initialize the variable
while(i<aSize)//or i<128
{
     cin>>arr[i];
     i++;
}

simply that code will keep getting data from user for thoe whole 128 elements (from 0 till 127)

128 is only suppose to be a potential for the array, I don't think you keep going regardless of what the user typed in, it's just a "validate the number" checker.

yes in the code above you keep going regardless of what the user typed in
however you need to check if the inputted value is -1 is so then you need to get out of the loop some how
to do that you can modify the code above to be like the following

int i=0,data;//we need another variable to check input data before assigning it to the array
while(i<aSize)//or i<128
{
     data>>arr[i];
     if(data==-1)//user typed -1 so get out of the loop using break statement
          break;
     else
     {
          arr[i]=data;//user didn't type -1 so assign input data to a new element in the array
          i++;
     }
}

I tried to write it simple as much as I could. I hope I could help