General Discussions

**quest23** · 05-04-2007, 03:49 PM

hey i need a program for this problem

-[FONT='Times New Roman','serif']Create a program that has a searchable array of 100 distinct positive integers between 0 and 1000. Your program should first create the 100 element array and fill it with random numbers. Once [/FONT][FONT='Times New Roman','serif']the[/FONT][FONT='Times New Roman','serif'] array is filled, you need to sort it using either a bubble or selection sort. Finally, you will ask the user to enter a number and the program will search the array to find whether it is contained [/FONT][FONT='Times New Roman','serif']among[/FONT][FONT='Times New Roman','serif'] the array's random numbers. The user will be rewarded with a message saying at which element the number was found, or else that the number was not found. The user will be prompted [/FONT][FONT='Times New Roman','serif']to[/FONT][FONT='Times New Roman','serif'] search for additional numbers if they wish and when the user finishes, the program will output the array in rows of ten numbers each.[/FONT]
[FONT='Times New Roman','serif'][/FONT]
[FONT='Times New Roman','serif']- thanks[/FONT]

**Village Idiot** · 07:21 PM

Unless there is some kind of pay, im not going to do all of it, but here is the sorting. Also, why didnt you take the time to make your message readable (no font tags)

ps. Am I doing your homework?

Quote:

#include <iostream>
using namespace::std;
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(int argc, char **argv)
{
//seed rand
srand( time(NULL) );

//the number of elements in the array
int elements=100;

//assign the array
int arr[elements];

//set each element
for(int i=0;i<elements;i++)
{
arr[i] = rand()%1000;
}

//this bool tells the loop to stop or continue
bool stop=false;

//this int holds the number while it is being swapped
int temp;

//sort them (this is bublesort)
while(stop == false)
{
stop = true;
for(int j=0;j<elements-1;j++)
{
if(arr[j] > arr[j+1])
{
temp = arr[j+1];
arr[j+1] = arr[j];
arr[j] = temp;
stop = false;
}
}
}

//display them
for(int k=0;k<elements;k++)
{
cout << arr[k] << "\n";
}
cout << "Press any key to exit";
//pause the program, any variable would work in place of temp
cin.get();

}

**chrishirst** · 05-05-2007, 05:20 AM

cross post with

http://www.webmaster-talk.com/coding...t-c-array.html