Hey guys. Like the title says I am trying to pass a php variable into a JS function.

This is what I have at the moment:

	function highlight(name)
		{
		document.name.src ="\images\rating\star2.gif";
		}	

<img src="\images\rating\star1.gif" onmouseover="highlight('<?php echo $count; ?>')" name="<?php echo $count; ?>">

When I hover the mouse over I get the error that: document.name is null or not an object.

Any suggestions?

What you do to pass from php to js is right, but what are you trying to do ?

There is no document.name property, and that's your error....
You are passing a "name" variable to your function, so reference it.
Your problem is to find the reference to the image.

For that, I either recommand you to put an id rather than a name on the image, and to use documnet.getElementById('the_id'); to find it back

function highlight(_id){
  var trg=document.getElementById(_id);
  trg.src ="\images\rating\star2.gif";
}
<img src="\images\rating\star1.gif" onmouseover="highlight('<?php echo $count; ?>')" id="<?php echo $count; ?>">

Or to put a reference on the image directly on the function call:

function highlight(trg){
  trg.src ="\images\rating\star2.gif";
}
<img src="\images\rating\star1.gif" onmouseover="highlight(this)" id="<?php echo $count; ?>">

Here, this reference to img from whose the onmouseover event trigerred, so no need to search it again.
I personally prefer to use this syntax, rather than to search for an id.

Extend the call to include every variables that you might need:

function highlight(_value, _elm){
  _elm.src ="\images\rating\"+_value+".gif";
}
<img src="\images\rating\star1.gif" onmouseover="highlight('<?php echo $count; ?>', this)" id="<?php echo $count; ?>">

I am just trying to make a Star rating system and I have no JS experience :P, but I figured I would just dive in.

Anyways I am trying to have it switch to a star on mous over and then on mouse out I will have it change back to an empty star.

But thanks for the pointer I will give it a try and see where I end up

Second question for you though first, If in the head I put a JS function and then within the JS function I put PHP code, if I call the JS function somewhere in the body will it execute the PHP code then?

If in the head I put a JS function and then within the JS function I put PHP code, if I call the JS function somewhere in the body will it execute the PHP code then?

Nope the PHP has run and finished before the page gets to the browser.

Thanks. Ya chris I figured that was the case, just thought that would be cool if that did work.