JavaScript Forum

**Tulork** · 07-22-2008, 02:26 PM

Why wont this work in any other browser then FireFox? It seems to be a problem with the browser check... but I've tried so many different methods for checking browser... nothing works.

fetch.js

Code:

function xmlhttpPost(strURL) {
    var xmlHttpReq = false;

    // Mozilla/Safari
    if (window.XMLHttpRequest) {
        xmlHttpReq = new XMLHttpRequest();
    }
    // IE
    if (window.ActiveXObject) {
        xmlHttpReq = new ActiveXObject("Microsoft.XMLHTTP");
    }
    
    xmlHttpReq.open('POST', strURL, true);
    xmlHttpReq.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
    xmlHttpReq.onreadystatechange = function() {
    
         
         if (xmlHttpReq.readyState == 1) {
            updatepage('<br /><br /><img src="loader.gif" border="0" alt="" style="margin-left:15px;" />');
        }

        
        if (xmlHttpReq.readyState == 4) {
            updatepage(xmlHttpReq.responseText);
        }
    }
    xmlHttpReq.send(getquerystring());
}

function getquerystring() {
    var form     = document.forms['feeds'];
    var word = form.feed.value;
    qstr = 'feed=' + escape(word);
    return qstr;
}

function updatepage(str){
    document.getElementById("result").innerHTML = str;
}

index.html

HTML Code:

<html>
<head>
<script type="text/javascript" src="js/fetch.js"></script>
</head>
<body>
<form name="feeds" action="index.html" method="POST">
  <select name="feed">  
  <option value="">Välj</option>
  <option value="http://www.geiser.se/feed" onclick='xmlhttpPost("show_feed.php")'>Geiser.se</option>
  <option value="http://feeds.feedburner.com/tkjblogg?format=xml" onclick='xmlhttpPost("show_feed.php")'>TkJ</option>
  <option value="http://www.dan.se/feed" onclick='xmlhttpPost("show_feed.php")'>Dan.se</option>
  </select><br />
  <div id="result"></div>
</form>
</body>
</html>

show_feed.php

PHP Code:


			
<?php
$url = $_POST['feed'];
    if(isset($_POST['feed']))
    {
        if(preg_match("/http:/", $url))
        {
            require_once("class_rss.php");        //Hämtar klassen
            $rss = new rssHandler();            //Skapar instans till klassen

                //Här anger du RSS-feedens url
            $antal = 20;                        //Här anger du hur många inlägg du vill skriva ut
            
            //Här skickar du in datan som klassen behöver och skriver ut den
            echo $rss->show_feed($url, $antal);
        }
    }
?>

I have tried without any checks in PHP... that isn't it. Everything works as it should in FF, but not in IE or Safari...

**chrishirst** · 07-22-2008, 08:04 PM

use the try ... catch exception method, it's more reliable

http://www.w3schools.com/ajax/ajax_browsers.asp

**JeremyMiller** · 07-23-2008, 01:08 AM

I use this...

Code:

  try {
    request = new XMLHttpRequest();
  } catch (trymicrosoft) {
    try {
      request = new ActiveXObject("Msxml2.XMLHTTP");
    } catch (othermicrosoft) {
      try {
        request = new ActiveXObject("Microsoft.XMLHTTP");
      } catch (failed) {
        request = false;
      }
    }
  }

  if (request) {
    //Success
  } else {
    //Error
  }

**saurabhj** · 07-23-2008, 02:35 AM

Quote:

Originally Posted by JeremyMiller

I use this...

Code:

  try {
    request = new XMLHttpRequest();
  } catch (trymicrosoft) {
    try {
      request = new ActiveXObject("Msxml2.XMLHTTP");
    } catch (othermicrosoft) {
      try {
        request = new ActiveXObject("Microsoft.XMLHTTP");
      } catch (failed) {
        request = false;
      }
    }
  }

  if (request) {
    //Success
  } else {
    //Error
  }

Yes this is best way (try and catch) and I am using the same code