Hi:

I'm using the following piece of code to print a form (HTML). Could you tell me whether I have it correct, or is something wrong with it?

echo "<form method=\"POST\" action=\"\">
<table width=\"100%\" border=\"3\" cellspacing=\"4\" cellpadding=\"2\" bordercolor=black align=\"center\">
<tr><th><input type=\"submit\" name=\"PRINT\" value=\"PRINT\" onClick=\"this.style.display=\'none\'; window.print()\"></th></tr>";


The slashes are being used because its part of PHP.

Thanks for your help!

I must admit that at the moment I don't know what "window.print()" does but IMHO there shouldn't be extra backslashes before single apostrophes. By the way, onClick should be written rather in small leters, so the code should look like this:

onclick=\"this.style.display='none'; window.print()\"

Hope, that was the source of your error...

It prints, thank you! It also prints the "PRINT" button. How do I make it only print the form without the print button?

Ehmm hmmm. Please give a bit more code, because for sth like that:

<?php
echo "<form method=\"POST\" action=\"\">
<table width=\"100%\" border=\"3\" cellspacing=\"4\" cellpadding=\"2\" bordercolor=black align=\"center\">
<input type=\"text\" value=\"sample\"/>
<tr><th><input type=\"submit\" name=\"PRINT\" value=\"PRINT\" onClick=\"this.style.display='none'; window.print()\"></th></tr>";
?>

I have only "sample" printed - it was in a border and also a border which comes from the table - but because of that: this.style.display='none'; the "PRINT" wasn't printed because before printing it was hidden, was it?

To remove the print button from printing only...

Put this in a separate CSS File:

input#Print {
	display: none;
}

link to it using this: (note media is set to print)

<link rel="stylesheet" media="print" href="/styles/print.css" />

The button should have it's ID set to Print (or whatever you decide, make sure to change it after tha # in step 1 above as well)

<input type="submit" id="Print" />

I must agree with pitbull82. I used it and it worked! Thanks also to Minaki for his tip. The only problem with Minaki's tip was that the form is created from existing data in the MySql database and thus his suggestion for using the CSS snippet would probably not work.

Thanks guys!