Hi,

i have a problem regarding mys javascript function.
i have several forms which name's like this:

PHP Code:

for($i=0; $i<$period; $i++)
{
  $queryCount= "select appId, appTypeName, appStatName from appointment where appId= '$appId'";
  $result= safe_query($queryCount);
  $num_rows = mysql_num_rows($result);
  while (list($appId, $appTypeName, $appStatName)= mysql_fetch_array($result))
  {
     print "<form name= \"bookAppointmentc$appId\" id= \"bookAppointmentc$appId\" action= \"../action/bookAppointment.php\" method= \"GET\">";
     print "<select name= \"appStatName\" class= \"onProgress\" onChange= \"return changeAppc$appId()\">\n";
     .....
     print "<a href= \"javascript: submitFormc$appId()\"> Changeaa </a> \n";
  }
} 


since i don't really good at javascript, i create the javascript func like this:

function bookAppointmentc1()
{
 ...
}

function bookAppointmentc2()
{
 ...
}

and so on..
i know it's wrong, but i don't know how to make it right?
or is there any other way in creating the form name in php?

thank's for your attention

Why would you want to create so many functions when you would simply have one function and pass the ID or the name of the form object? It is a formula destined for disaster.

you would simply need;

function BookAppointment(objID) {
...
}