Dim ProcessStartInfo As New System.Diagnostics.ProcessStartInfo()
ProcessStartInfo.FileName = "C:\MyBatchFile.bat"
ProcessStartInfo.Arguments = "" ' your parameters here, if any
ProcessStartInfo.WorkingDirectory = "C:\"
ProcessStartInfo.WindowStyle = ProcessStartInfo.WindowStyle.Maximized
ProcessStartInfo.UseShellExecute = True
ProcessStartInfo.CreateNoWindow = False
System.Diagnostics.Process.Start(ProcessStartInfo)
Something along those lines should do it...
__________________ Minaki Serinde MCP
"Wow, Linux is nearly on-par with Windows ME!"