Hi,
I have this php search script, but when I run it I just get this

country:
type:
Abstract:

This is the right layout but it is not filling it with results.
The php code is

PHP Code:

<?php 
// Connects to your Database 
mysql_connect("localhost", "adder", "clifford") or die(mysql_error()) ; 
mysql_select_db("real") or die(mysql_error()) ;
$country = isset($_POST['menuFilesDMA']) ? preg_replace('/[^a-zA-Z0-9\ ]/', '', $_POST['menuFilesDMA']) : ''; 
$type = isset($_POST['Type']) ? preg_replace('/[^a-zA-Z0-9\ ]/', '', $_POST['Type']) : ''; 
$Abstract = isset($_POST['keyword']) ? preg_replace('/[^a-zA-Z0-9\ ]/', '', $_POST['keyword']) : ''; 
if ($country) { 
     $where[] = "country='$country'"; 
} 
if ($type) { 
     $where[] = "type='$type'"; 
} 
if ($Abstract ) { 
     $where[] = "Abstract LIKE '%$Abstract%'"; 
} 
if ($where) { 
     $sql = "SELECT * FROM items WHERE " . implode(' AND ', $where); 
     // query and display results 
} 
 
{ 
//Outputs the image and other data
Echo "<b>country:</b> ".$info['country'] . "<br> "; 
Echo "<b>type:</b> ".$info['type'] . " <br>"; 
Echo "<b>Abstract:</b> ".$info['Abstract'] . " <hr>"; 
} 
?>

Any help would be much appriciated,
Thanks,
Colin

I could not locate the following code where you run the query and fetch the results into an array:

$result=mysql_query($sql) or die(mysql_error().$sql);
$info=mysql_fetch_array($result);

I presume you have already done a echo $sql to check if it is as expected.