PHP Forum

**MGT-Evelath** · 09-16-2007, 04:36 PM

Well, I attempted to handle this assignment on my own, but it's gotten to the point that I need assistance. I am making a Converter. From Fahrenheit to Celsius, and I can't seem to get my current code to work:

Code:

<html>
<head> 
<title>Temperature Conversion</title> 
</head> 
<body> 
<h2>Temperature Conversion</h2> 


<form method="post"
      action="<?php echo $_SERVER['PHP_SELF']; ?>">
Fahrenheit:
<input type = "text" name = "fTemp"> 
<br>
Celsius:
<input type = "text" name = "cTemp">

<br> 
<input type = "submit"> 
</form> 

<?



{
    
  if(isset($_POST['fTemp']))
  $cTemp = (float)(($fTemp - 32) / 1.8 );
}
    


{
  if(isset($_POST['cTemp']))
  $fTemp = (float)(1.8 * $cTemp) + 32;

}


?>

</body>
</html>

It doesn't come up with any errors, and i've tried about 100 forms of this code. I just can't get the information processed and output into the same box.

**flann** · 09-16-2007, 05:00 PM

in the input text box, you need to place:

PHP Code:


			
<input type='text' name='fTemp' value='<?=$_POST['fTemp']?>'>

**MGT-Evelath** · 09-16-2007, 05:40 PM

Code:

<html>
<head> 
<title>Temperature Conversion</title> 
</head> 
<body> 
<h2>Temperature Conversion</h2> 


<form method="post"
      action="<?php echo $_SERVER['PHP_SELF']; ?>">
Fahrenheit:
<input type = "text" name = "fTemp" value='<?=$_POST['fTemp']?>'> 
<br>
Celsius:
<input type = "text" name = "cTemp" value='<?=$_POST['cTemp']?>'>

<br> 
<input type = "submit"> 
</form> 

<?



{
    
  if(isset($_POST['fTemp']))
  $cTemp = (float)(($fTemp - 32) / 1.8 );
}
    


{
  if(isset($_POST['cTemp']))
  $fTemp = (float)(1.8 * $cTemp) + 32;

}


?>

</body>
</html>

However nothing occurs when I input the amount.

**Kuldeep2195** · 09-16-2007, 08:52 PM

Try this:

PHP Code:


			
<?
{
  if(isset($_POST['fTemp']))
  $cTemp = (float)(($fTemp - 32) / 1.8 );
}
{
  if(isset($_POST['cTemp']))
  $fTemp = (float)(1.8 * $cTemp) + 32;
}
?>
<html>
<head> 
<title>Temperature Conversion</title> 
</head> 
<body> 
<h2>Temperature Conversion</h2> 

<form method="post"
      action="<?php echo $_SERVER['PHP_SELF']; ?>">
Fahrenheit:
<input type = "text" name = "fTemp" value='<?=$fTemp?>'> 
<br>
Celsius:
<input type = "text" name = "cTemp" value='<?=$cTemp?>'>

<br> 
<input type = "submit"> 
</form> 
</body>
</html>

**MGT-Evelath** · 01:58 AM

There is still no output. =/

Thanks for the assistance thus far.

**Kuldeep2195** · 09-17-2007, 02:35 AM

Made some changes and also tested it.

PHP Code:


			
<?
if($_POST['fTemp'] >' ')
{
    $fTemp = $_POST['fTemp'];    
    $cTemp = (float)(($fTemp * 1.0 - 32) / 1.8 );
}
else
{
    $cTemp = $_POST['cTemp'];    
    $fTemp = (float)(1.8 * $cTemp) + 32;
}
?>
<html>
<head> 
<title>Temperature Conversion</title> 
</head> 
<body> 
<h2>Temperature Conversion</h2> 

<form method="post"
      action="<?php echo $_SERVER['PHP_SELF']; ?>">
Fahrenheit:
<input type = "text" name = "fTemp" value='<?=$fTemp?>'> 
<br>
Celsius:
<input type = "text" name = "cTemp" value='<?=$cTemp?>'>

<br> 
<input type = "submit"> 
</form> 
</body>
</html>