I seem to be lost trying to format a double conditinal statement.

This is the pseudo lines:
if $POST['active'] is not equal to 0 or 1
{do this}
else

This does not work:

PHP Code:

if (($POST['active'] != 0) || ($POST['active'] !=1)) 


Can you tell me what I am doing wrong?

TIA

Well you could use

PHP Code:

if (!($POST['active']>=0 && $POST['active'] <=1))   {... 


edited to add i'm taking as read that you can't use

PHP Code:

 if ($POST['active']>1) {... 


You just have a logical error. When you say not equal to "0 or 1", what you mean is not equal to 0 and not equal to 1. This code fixes the problem and demonstrates it working as described:

PHP Code:

<?php
if (($_POST['active'] != 0) && ($_POST['active'] != 1))  {
  echo "Is NOT 0 or 1";
} else {
  echo "Is 0 or 1";
}
?>
<form method="post">
<select name="active">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
</select>
<input type="submit" value="Check" />
</form>

Also, it's $_POST, not $POST.

You just have a logical error. When you say not equal to "0 or 1", what you mean is not equal to 0 and not equal to 1. This code fixes the problem and demonstrates it working as described:

Jermy that may be exactly what I had. My logic flaw sounds right. Unfortunately at this moment I have had a couple of adult beverages too many to try it out.

I did save it and will follow up on this thread.

lol. Well, the code I provided should help you out as it's very basic and demonstrates what I believe you wanted. I hope you didn't take my assertion of a flaw in logic as personal. I re-read that and it may have come across as worse than I intended -- I was just speaking of logic from a mathematician's point of view...time for me to get in on some of those adult bevs too.

I hope you didn't take my assertion of a flaw in logic as personal.

Absolutely not! That is exactly what it was. One would need a pretty thin skin to be upset by that statement.

Rep added and thanks.