PHP Forum

**nlassiter** · 02-07-2008, 08:02 PM

Code:

<input type='text' name='en_ch_date' value='<? echo date(("Ymd"), strtotime("-3 days")); ?>'>

This correctly outputs 20080204 with today being 20080207.

I want to put a variable in for -3 which will change but currently has a value of 100. How do I go about putting a variable in this function?

**nlassiter** · 02-07-2008, 08:33 PM

Also how would you add the date() function in a sql query?

Code:

 VALUES ('$_POST[mach_id]','Engine Oil','date("Ymd")','$_POST[en_ch_hours]')";

**nlassiter** · 02-12-2008, 04:42 PM

Does anyone know?