PHP Forum

**jake5253** · 08-08-2004, 11:01 PM

PHP Code:


			
<?php

$picture_source = $_GET['src'];

?>

<html>

<body>

<img src="<?php echo $picture_source ?>">

</body>

</html>

This was posted in another thread, how do you get that to include another php page?

**andrews_john** · 08-09-2004, 03:14 AM

you need to send a variable to a page? you may do it like a
<a href=yourpage.php?yourvar=yourvalue>

or you may send it trough standard form....

**Dark-Skys99** · 08-09-2004, 07:39 AM

If you want to include a php page depending on the varibale...

this hould help...

PHP Code:


			
<?php

 $page = $_GET['page'];



//What to do if no page is specified in the variable

if (!$page){



$page = 'mainpage.php';



}



//include the page

include $page;

?>

This way if you typed..
pagename.php?page=page.php
it would inlude the page.php page

But if you want it so that you can type..

pagename.php?page=page1
pagename.php?page=page2
etc.

and you can then specify what page loads...this would do...

PHP Code:


			
<?php

 $page = $_GET['page'];



//What to do if no page is specified in the variable

if(!$page){



$page = 'mainpage.php';



}



if($page == page1) {



$page = 'pagenumber1.php';



}



if($page == page2) {



$page = 'soemotherpage.php';



}



//You can then add as many more pages you want in the same way



//include the page

include $page;

?>

So if you typed..
pagename.php?page=page1
it would load pagenumber1.php

Hope this makes sense

Need any more help just ask

-James