woops i forgot 'quotes'
PHP Code:
<?php session_start(); // starts sessions include "../settings.php"; // inlcudes config
switch ($_GET[friends]) { //allows multiple pages default: $id = $_SESSION['user_id']; $get_username_value = get_username($id); $get = "SELECT * FROM `friend_requests` WHERE `by_user` = '$get_username_value'"; $result= mysql_query($get) or die("QUERY ERROR:<br />{$get}<br />" . mysql_error() ); //gets requests
{
echo ( "Friend Requests $reqs[username] wants to be friends with you. <a href='newfriends.php?friends=accept&user=$reqs[username]'>Accept</a><br/> <a href='newfriends.php?friends=delete&user=$reqs[namername]'>Delete</a>" ); //displays requests and shows accept delete links } break;
case 'accept': //accept page if ($_GET[user]) { //get username $get_username_value = get_username($id); $add = mysql_query( "INSERT INTO `friends` (`friendname` , `username`) VALUES ('$_GET[user]' , '$get_username_value') "); // add to your friends list $delete = mysql_query( "DELETE FROM `friend_requests` WHERE `by_user` = '$_GET[user]' "); // deletes friend request echo ( "$_GET[user] has been added as a friend and the request has been deleted" ); // echos the completion } break; //ends accept page
case 'delete': // delete page if ($_GET[user]) { //gets username $delete = mysql_query( "DELETE FROM `friend_requests` WHERE `by_user` = '$_GET[user]' "); // deletes friend request echo ( "$_GET[user]'s request has been deleted" ); // echos completion } break; //ends delete page } // ends switch
?>
now i im stuck,,, need some advie lol. ok the code doents pull the username of the person that wants to be accepted as a friend
i just get /members/newfriends.php?friends=accept&user=??
how would i pull the user name out so i can have
Name wants to be friends with you. Accept or Delete
and how would you go about making it so that a message is displayed when there is a user waiting to become a friend?
sorry i forgot to think this part through
|