I have been working on this for the past hour or two but I want to make my script where it shows only the three latest news post on my homepage, and not any more here is my code. Anyone have any ideas? Below is the site address so you can view what i have done with it.

http://www.aa1intelligence.com/development/

PHP Code:

<?php
    require ('connect.php'); // connect to database
    
    // Retrieve News
    $query = 'SELECT * FROM newsentries ORDER BY date_entered DESC';
    
    if ($r = mysql_query ($query)) { // Run the query.

        // Retrieve and print every record.
        while ($row = mysql_fetch_array ($r)) {
            print "<div align=\"center\"><img class=\"newsimgheader\" src=\"lib/image/site_img/news/newsheader.jpg\"/></div><table class=\"newstable\" border=\"0\" cellpadding=\"8\" cellspacing=\"0\" bordercolor=\"#CCCCCC\" align=\"center\" width=\"98%\"><tr><td><h1 class=\"newsheader\">{$row['title']}</h1><hr class=\"newshr\"><p class=\"newsentry\">{$row['entry']}</p><hr class=\"newshr\"><p class=\"newsfooter\">{$row['date_entered']}&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;Posted By:&nbsp;{$row['added_by']}</td></tr></table><div align=\"center\"><img class=\"newsimgfooter\" src=\"lib/image/site_img/news/newsfooter.jpg\"/></div>";
    }

    } else { // Query didn't run.
        die ('<p>Could not retrieve the data because: <b>' . mysql_error() . "</b>. The query was $query.</p>");
    } // End of query IF.

mysql_close(); // Close the database connection.
    
?>

I found out how to do it, thank you anyways, sorry for wasting time