Im looked everywhere and maybe someone knows how.

Im trying to make this into a working Button becasue the script i have im hiding links

i have it like

if($this1 < $nume) { 
print "<a href='$page_name?start=$next'> <font face='Verdana' size='3'><button><b>Next</b></button></font> </a>";}
else {

But i wanted to hide links so i have this in

A:visited {
display:none;
}

but becasue it has "<a href= it counts it as a link and hide it as well.

I tryed makeing it into a Full button like

<button onClick="window.location='URL" style="color:#FFFFFF;background: url('/graphics/nav.gif'); width: 101px;">TEXT</button>

it does not work so if anyone know anything i can do about this be great thanks.

What is this ???
There are no <button> elements in html...
Honestly, you should revise your HTML bases...

Button are part of a form. To have a button somewhere, you must first declare the form, and then add inputs of type button it it.

<form ...>
  <input type="button".../>
</form>

And just to help you further, I will let you search what should be put in place of ...
Your first stop should be http://www.w3schools.com

I don't understand what you are trying to do. Be more clear and with your code also.

There is you know button

That one got me yesterday as well and I had to look it up, 'cos I thought they were inventing elements and wondering why it didn't work.

Originally Posted by chrishirst

There is you know button

That one got me yesterday as well and I had to look it up, 'cos I thought they were inventing elements and wondering why it didn't work.

Okay... You learn something new every day.
I'll try to remember it, but not sure. The input type=button is engraved somewhere in my brain so vividly, than surely it'll stay my first go.

<button>? I didn't know that one either. Geeze, that is bad, I'm supposed to be a front-end pro... I guess I'll give up, and go back to making cupcakes at the cupcake factory.

***EDIT***
I was reading up on this a bit more, and apparently you can place regular HTML you like inside of a button. This, for example, is perfectly valid:

<button type="button">
    <ul>
        <li>Hello</li>
        <li>World</li>
    </ul>
</button>

The above will validate, as long as the button is contained by a block-level element such as a <p> or a <div>.

Hi thanks for the msg's back but im not trying to make a norm button.

This right here is a turn page function

PHP Code:

if($this1 < $nume) { 
print "<a href='$page_name?start=$next'> <font face='Verdana' size='3'><b>Next</b></font> </a>";}
else { 


once clicked it will pull more info from the DB and display it.

But what im doing is once the info is up and displayed i have it so once u click on it it's hides

Display none for the img's but i also want the same thing to happin for the links.

but because the turn page function is a link when i enable the links to hide once clicked the turn page function link it hides. now to try to get around this i need to make it into a button.

but once putting a button funtion into.

PHP Code:

if($this1 < $nume) { 
print "<button onClick="window.location="$page_name?start=$next'" style="color:#FFFFFF;background: url('/graphics/nav.gif'); width: 101px;">Next</button>";}
else { 


i get errors.. So hoply that is more clear for you and you understand what i am trying to do better.

Thanks.

PHP Code:

print "<button onClick="window.location="$page_name?start=$next'" style="color:#FFFFFF;background: url('/graphics/nav.gif'); width: 101px;">Next</button>";} 


is invalid, because you fail to backslash your quotes, like this:

PHP Code:

print "<button onClick=\"window.location=\"$page_name?start=$next\" style=\"color:#FFFFFF;background: url('/graphics/nav.gif'); width: 101px;\">Next</button>";} 


i tryed this but and it displayed fine but the action didnt work.

Why don't you try assigning a css id/class to the links for the button and simply override the "display:none" of the default links?!

The problem (I believe) is that a <button> will just create a push button - something that can trigger an onClick in javascript instead of using a hyperlink.

In order to make that button DO anything, you need to create it as a form submit button, that will POST your data back to the server, where your script can query the next batch of data from the db and move the user along.

Why would you want to do this via javascript, when it's an incredibly basic function of form data interacting with PHP? Perhaps in the case of an AJAX call to refresh data without reloading the page, but in that case, the onClick should call a javascript function that makes the xmlHttp request to the server and replaces the content of your div with the paginated data.

I don't believe (personally, and I could be wrong) that you will EVER get that button to do anything the way it is coded there. It isn't submitting any data to the server to run your script and return the new data.