Hiya,
I know how to merge variables together

PHP Code:

$var = 'http://www.'
$var2 = 'google.com'
$var3 = $var . $var2; 


But how to I inject the variables into a include URL
For example.

PHP Code:

<?
$id1 = 300
$id2 = 500
$dataURL = 'http://mysite.com/test.php?id='.$id1.'&id2='.$id2.''; #<-- only has 1 apostrophy but wont show in post
echo ($dataURL);
?>

As far as I am aware all it's doing is including the page as
http://mysite.com/test.php?id=&id2=
instead of
http://mysite.com/test.php?id=300&id2=500

hi there,

in your post you say you want to "inject the variables into an include URL".. by that I assume you are using the include function... which isn't in your example... but anyway if you are including a url you wont need to assign the url the variables, as long as they are available on the parent page then then included page will see them too ...

PHP Code:

$var = "test";
include ('this.php'); 


test.php can call $var and will see "test", you dont need to do anything more
[/php]

Well, I do need to inject it into the fetched URL because its an external page.
It needs to point to specific id.

PHP Code:

<?
$id1 = 300
$id2 = 500
$dataURL = 'http://mysite.com/test.php?id='.$id1.'&id2='.$id2.''; #<-- only has 1 apostrophy but wont show in post
$result = file_get_contents($dataURL);
echo ($result);
?>

I forgot to include $result = file_get_contents($result);

I see, I'm with you..

well that above code works fine for me... what version of PHP are you using?

Try ..

PHP Code:

$id1 = 300;
$id2 = 500;
$dataURL = "http://mysite.com/test.php?id=$id1&id2=$id2"; #<-- only has 1 apostrophy but wont show in post
echo ($dataURL); 


Sorry, it was my stupid mistake...
I had a mistype in the URL and it was only displaying the default page....

Sorry for wasting your time
I used '.$id1.'&id2='.$id2.' as i find it alot easier to read within the code.

Thanks for your replies
Added to your talkupation thingy

ok excellent