This is my PHP script.This file is working in my localsystem, i am using WAMP server in localsystem.
But when i hosted the files in the server, nothing is working..

<object id="flashmovie" type="application/x-shockwave-flash" data="gallery.swf" width="100%" height="100%">
<param name="movie" value="gallery.swf" />
<param name="FlashVars" value="<? if(isset($_GET["image"])) echo "topimage=".$_GET["image"] ?>" />
</object>

Pls help

It would help if you posted the actual, currently generated output from your server, but I'm going to take a stab in the dark and say "short tags".

Change the '<?' before your if into a '<?php' and see if that works.

It might we the <?php mistake

but somtimes "I don't know why" isstet doesn't work in small letter but written with caps on ISSET it does work...

Good luck

You've forgotten a semi-collin here I think:

if(isset($_GET["image"])) echo "topimage=".$_GET["image"]; ?>

also isnt it normally a single quote in the $_GET ?

i.e.

PHP Code:

if (isset($_GET['image'])) { 


or does it not matter?

I believe the line

PHP Code:

<param name="FlashVars" value="<? if(isset($_GET["image"])) echo "topimage=".$_GET["image"] ?>" />

would produce something in the format <param name="FlashVars" value="topimage=example.jpg" />

Do you need the 'topimage=' part as I'm not aware of a topimage attribute for param. If you need this, you may need to output as two variables $_GET['value'] and $_GET['image'] like

PHP Code:

<param name="FlashVars" value="<?php if(isset($_GET['value'])) echo $_GET['value'] ?>" topimage="<?php if(isset($_GET['image'])) echo $_GET['image']; ?>" />

or if you need just the image variable output as value

PHP Code:

<param name="FlashVars" value="<?php if(isset($_GET['image'])) echo $_GET['image']; ?>" />

Hope this helps