I keep getting this error:


Fatal error: Call to a member function addActiveGuest() on a non-object in /home/XXXX/domains/XXXX/public_html/home/include/session.php on line 58

Line 55 to 59:

PHP Code:

if(!$this->logged_in){
         $this->username = $_SESSION['username'] = GUEST_NAME;
         $this->userlevel = GUEST_LEVEL;
         $database->addActiveGuest($_SERVER['REMOTE_ADDR'], $this->time);
      } 


Can you post the code where $database is set?

Okay, I fixed that problem I think. But created a new one. I was told by someone that "now you just have an object that isnt correctly instantiated on line 7"

Because I got this error

PHP Code:

Fatal error: Call to a member function query() on a non-object in /home/dominic/domains/ohio-host.com/public_html/home/index.php on line 7 


Line 1 to 13:

PHP Code:

<?php
include './u&ainclude/mainlayout.php';

function displayNews(){
   global $database;
   $q = "SELECT name,subname,date,type,content FROM ".TBL_NEWS." ORDER BY date DESC,date";
   $result = $database->query($q);
   /* Error occurred, return given name by default */
   $num_rows = mysql_query($result);
   if(!$result || ($num_rows < 0)){
      echo "Error displaying info";
      return;
   }

$database->query() is not defined. Check that query() has been set somewhere.

Well, what do you mean? Like so I should put query() somewhere?

Call to a member function on a non-object means that $database is not an object. Most likely this means that $database is not being initialized.

Where is $database being set?

I'm very illiterate when it comes to PHP. Would it help if I packed up the script it sent it to you? Because this is very confusing for me.

What it means is that somewhere in your code before that function gets called you need to have a line that looks something like...

$database = new DatabaseClassName('param1', 'param2', 'etc');

The database class name would be whatever class is your database class, and the parameters may or may not be required. Basically you are not initializing/instantiating the $database variable before calling that function.

NullPointer, markAtRitetek or someone else how can help me is it possible that you can look at my code.. i have a similar problem en i'm not that good in php?

PHP Code:

    <?php
    
                // Check to see if we have been sent from update.php
                // If so, alert that an update was successful            
                if(isset($_GET['message'])){
                    echo "<p><font color='red'>Wijzigingen opgeslagen</font></p>";
                }
    
        require("connection.php");
            // Load in the content of the current viewing page from the MySQL database
            $page = (isset($_GET['page'])) ? $_GET['page'] : "1";
            $sql = "SELECT id, content FROM pages WHERE id='$page'";
            $result = $conn->query($sql) or die(mysqli_error());
            if($result){
                $row = $result->fetch_object();
                echo '<form method="post" action="update.php">';
                echo '<input type"hidden" name="id" value="' . $row->id . '" />';
                echo '<textarea name="content" cols="70" rows="20">';
                echo $row->content;
                echo '</textarea>';
                echo '<input type="submit" name="editContent" value="Opslaan" />';
                echo '</form>';
            }
    
    ?>
    </div><!--editor-->
    <div id="webpag">
    <ul>
    <?php
                // Display all the pages that we can edit
                $sql = "SELECT id, name FROM nav";
                $result = $conn->query($sql) or die(mysqli_error());
                if($result){
                    while($row = $result->fetch_object()){
                        echo "<li><a href='webpag_updaten.php?page={$row->id}'>{$row->name}</a></li>";                    
                    }
                }
    ?>