I'd like to create a conditional include that will display content only if the include file is present.

Here's my include as it is scripted now:

PHP Code:

<?php
// import file
include("wp-content/plugins/stuff.inc");
?>

How would I add a conditional statement that would display nothing if stuff.inc is not present?

Thanks

If stuff.inc exists as an empty file nothing will be displayed. If it has content that will be displayed.

If you try to include it and it does not exist you get the error message. @include might supress that message. I do not know for sure.

PHP Code:

if(file_exists("wp-content/plugins/stuff.inc"))
{
     include("wp-content/plugins/stuff.inc");
}

//OR
@include("wp-content/plugins/stuff.inc"); 


It looks to me like you are writing a wordpress plugin. If this is the case, I suggest you include files like this:

PHP Code:

include(dirname(__FILE__) . 'stuff.inc'); 


Later versions of wordpress allow you to move the plugin directory so specifying it as wp-content/plugins/ will reduce compatibility.

Excellent answers.

Thanks to you both!

An alternative to "file_exists()" - would be to use "is_file()" function which checks whether file name exists and whether the file is regular.