how do you convert a var[#] to a string, what im trying to do is load a image file with the string from the var[#] but the script reads the image as var[#].bmp instayed of the string that the var[#] represents

Is var[#] an array? Try print_r or var_dump.

thanks for all the help nullpointer,
unfortunelty nither of thoes solutions worked, print_r comes back as 1 and var_dump comes back as null,

my main issue is with this

echo '<img src="($expo[1]).bmp" width="50" height="50">';

(its at the bottem im trying to test it before adding it to the loop)
im sure thats entirely wrong, i may of been closer with other wrong attempts but this is where my back button takes me , when the site loads, the image thats spose to load comes up as ($expo[1]).bmp instayed of its target,

this is the full page

<?php
$i = 0;
$linenum = $i ;
$path = "map2.txt"; 
$handle = fopen($path, "r"); 
$lines=file($path); 
$string[$i] = ($lines[$linenum]);  
$expo = (explode("|",($string[$i])));
$string2[$i] = str_word_count($string[$i]) ; //get Len //
 
$counter = 0;
while ( $counter <= 10 ) {
  $expo = (explode("|",($lines[$counter])));
  echo ($expo[1]);
  echo ($expo[2]);
  echo ($expo[3]);
  echo ($expo[4]);
  echo ($expo[5]);
  echo ($expo[6]);
  echo ($expo[7]);
  echo ($expo[8]);
  echo ($expo[9]);
  echo ($expo[10]);
  echo "<BR />"; 
  echo str_word_count($lines[$counter]);
$expo = (explode("|",($lines[$counter])));
  echo "<BR />"; 
 $counter = $counter + 1;
 }

echo '<img src="($expo[1]).bmp" width="50" height="50">';
 
?>

this is map2.txt

a1|b1|c1|d1|e1
a2|b2|c2|d2|e2
a3|b3|c3|d3|e3
a4|b4|c4|d4|e4
a5|b5|c5|d5|e5

Strings surrounded with single quotes ( ' ) are not parsed so

PHP Code:

echo '<img src="($expo[1]).bmp" width="50" height="50">'; 


will literally output the string <img src="($expo[1]).bmp" width="50" height="50">

Variables are parsed in double quotes, however. In some cases you need to surround your variables with braces {}, not parens () to indicate that the variables needs to be parsed. Try:

PHP Code:

echo "<img src=\"{$expo[1]}.bmp\" width=\"50\" height=\"50\">"; 


yea that works, took some fiddleing around with tho, after the loop it seems to of forgot what expo[0] is, is there a way to read a exploded array, with two integers, like expo[0][0] or is the best way to store them in other arrays as i make them

thanks you again,

PHP Code:

print_r($expo); 


That should display all of the values in the array. The output is plain text, not html so it is easier to read if you view the source rather than just the browser output.

is it possible to place a image ontop of another image

It is possible to parse strings within single quotes:

PHP Code:

echo '<img src="'.($expo[1]).'.bmp" width="50" height="50">'; 


Originally Posted by moatist

It is possible to parse strings within single quotes:

PHP Code:

echo '<img src="'.($expo[1]).'.bmp" width="50" height="50">'; 


The string isn't parsed, it is three seperate strings appended together. In double quotes the string itself is parsed.