PHP Code:

<?php
if ($squarefeet == 1500) {
echo "<p><img src=\"1500.gif\">";
} if else ($squarefeet == 2000) {
echo "<p><img src=\"2000.gif\">";
} if else ($squarefeet == 2500) {
echo "<p><img src=\"2500.gif\">";
} if else ($squarefeet == 3000) {
echo "<p><img src=\"3000.gif\">";
} if else ($squarefeet == 3500) {
echo "<p><img src=\"3500.gif\">";
} if else ($squarefeet == 4000) {
echo "<p><img src=\"4000.gif\">";
}
?>

Is there something wrong with this code? I keep getting this error:

Parse error: syntax error, unexpected T_ELSE, expecting '(' in /home/ingrams/public_html/system-selector/geothermalcalculator.php on line 11

Line 11 is } if else ($squarefeet == 2000) {

I dont understand why I am getting this error.

Anyone else know why? Is it a problem with the syntax?

All the "if else" should be "else if", or evan "elseif" since php has introduced that keyword aswell. If you want to get rid of some if() statements you could also use switch(). It will do the same thing, some people think it looks better some people don't :P

PHP Code:

switch($squarefeet) {
   case 1500:
      echo "<p><img src=\"1500.gif\">";
      break;
   case 2000:
      echo "<p><img src=\"2000.gif\">";
      break;
   case 2500:
      echo "<p><img src=\"2500.gif\">";
      break;
   case 3000:
      echo "<p><img src=\"3000.gif\">";
      break;
   case 3500:
      echo "<p><img src=\"3500.gif\">";
      break;
   case 4000:
      echo "<p><img src=\"4000.gif\">";
      break;
} 


Or in this case, where the different cases are so similar, you can do like this. Again, it's just a question of which way you like the best, all of them will work.

PHP Code:

$allowed = array(1500, 2000, 2500, 3000, 3500, 4000);
$size = in_array($squarefeet, $allowed) ? $squarefeet : 1500;
echo "<p><img src=\"$size.gif\">"; 


wow i feel stupid lol. my dyslexia kicked in i guess

if else = else if

thank you!