Hi,
I am a newbie in php and needs to populate triple drop down list.
Luckily I got the code but its not working.
Here's the code I am using, please let me know if I mistook somewhere.
Creating tables in database:
PHP Code:
CREATE TABLE `country` (
`id` tinyint(4) NOT NULL auto_increment,
`country` varchar(20) NOT NULL default '',
PRIMARY KEY (`id`)
) TYPE=MyISAM ;
CREATE TABLE `state` (
`id` tinyint(4) NOT NULL auto_increment,
`countryid` tinyint(4) NOT NULL,
`statename` varchar(40) NOT NULL,
PRIMARY KEY (`id`)
) TYPE=MyISAM ;
CREATE TABLE `city` (
`id` tinyint(4) NOT NULL auto_increment,
`city` varchar(50) default NULL,
`stateid` tinyint(4) default NULL,
`countryid` tinyint(4) NOT NULL,
PRIMARY KEY (`id`)
) TYPE=MyISAM ;
All created successfully.
the index.php file
PHP Code:
<form method="post" name="form1">
<table border="0" cellpadding="0" cellspacing="0" width="60%"><tbody>
<tr>
<td width="150">Country</td>
<td width="150"><select style="background-color: #ffffa0" name="country" onchange="getState(this.value)"><option>Select Country</option><option value="1">USA</option><option value="2">Canada</option> </select></td>
</tr>
<tr>
<td>State</td>
<td>
<p id="statediv">
<select style="background-color: #ffffa0" name="state"><option>Select Country First</option> </select></td>
</tr>
<tr>
<td>City</td>
<td>
<p id="citydiv">
<select style="background-color: #ffffa0" name="city"><option>Select State First</option> </select></td>
</tr>
</tbody></table>
</form>
[b]getState() function of the javascript[/b]
function getState(countryId)
{
var strURL="findState.php?country="+countryId;
var req = getXMLHTTP();
if (req)
{
req.onreadystatechange = function()
{
if (req.readyState == 4)
{
// only if "OK"
if (req.status == 200)
{
document.getElementById('statediv').innerHTML=req.responseText;
} else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
[b]
The code of the PHP file findState.php.
[/b]
<? $country=intval($_GET['country']);
$link = mysql_connect('localhost', 'root', ''); //I changed this to my database, host, user and password.
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('db_ajax');
$query="SELECT id,statename FROM state WHERE countryid='$country'";
$result=mysql_query($query);
?>
<select name="state" onchange="getCity(<?=$country?>,this.value)">
<option>Select State</option>
<? while($row=mysql_fetch_array($result)) { ?>
<option value=<?=$row['id']?>><?=$row['statename']?></option>
<? } ?>
</select>
[b]getCity() function[/b]
function getCity(countryId,stateId)
{
var strURL="findCity.php?country="+countryId+"&state="+stateId;
var req = getXMLHTTP();
if (req)
{
req.onreadystatechange = function()
{
if (req.readyState == 4) // only if "OK" <--I don't understand this.<--
{
if (req.status == 200)
{
document.getElementById('citydiv').innerHTML=req.responseText;
} else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
[b]the code of findcity.php,[/b]
<?php $countryId=intval($_GET['country']);
$stateId=intval($_GET['state']);
$link = mysql_connect('localhost', 'root', ''); //I changed this to my database, host, user and password.
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('db_ajax');
$query="SELECT id,city FROM city WHERE countryid='$countryId' AND stateid='$stateId'";
$result=mysql_query($query);
?>
<select name="city">
<option>Select City</option>
<?php while($row=mysql_fetch_array($result)) { ?>
<option value><?=$row['city']?></option>
<?php } ?>
</select>
It seems functions isn't working. I select the Country from the combo but it doesn't change the state.
I've done some manual entries in database according the table structure.
Any help would be highly appreciated.
