I am still a newbie to PHP, and I have a foreach loop issue. The section of code is the following:

	foreach($word[0] as $value)
		{
		foreach($num[0] as $value2)
				{
    $tags = array('<td>','</td>','<td width=\'85\'>','<td align=right>');
				echo str_replace($tags, "",$value)." ".str_replace($tags, "",$value2)."<br>".$vbCrLf;
				}			
		}

The echoed results show each word ($value) as expected, but the number ($value2) next to each word is the same. For example:
word1 45
word2 45
word3 45

After it loops througn each word, it then echoes the first word, with the numbers changing as they should. For example:
word1 65
word1 49
word1 23

I am trying to get the result to show each word next to each number like:
word1 65
word2 49
word3 23

I tried using arrays to no success, finding I couldn't put the values of $word[0] and $num[0] into an array correctly if it's even possible. PHP Gurus, I would greatly appreciate any suggestions to this problem. Thanks!

The problem is you are using two loops (nested) to iterate two arrays. You need to either use two distinct loops or a single loop like so:

PHP Code:

$tags = array('<td>','</td>','<td width=\'85\'>','<td align=right>');
for($i = 0; $i < count($word[0]); $i++)
{
     $value = $word[0][$i];
     $value2 = '';
     if($i < count($num[0]))
     {
          $value2 = $num[0][$i];
     }
     echo str_replace($tags, "",$value)." ".str_replace($tags, "",$value2)."<br>".$vbCrLf;
} 


Also notice how I took $tags outside of the loop. If it were in the loop the value would be reassigned for every iteration.

That works perfectly! NullPointer, you're a GOD! Thanks.