Hi,

I am making a user feedback form and I've to ask for a image for that......so I am using file element but its not saving anything in the database in the field I've made for that......

Here's the more info....

This is how I've defined file element.

PHP Code:

<input name="file" id="file" class="ftextbox1" tabindex="6" type="file"> 


Here's I am using inside my filese...

PHP Code:

$fbimg = $userfback->upload_file_art($_FILES['file'],"../img/uimg/"); 


Here's the function upload_file_art

PHP Code:

function upload_file_art($file, $path)
    {    
        $filename = rand(1000,9999)."_".$file["name"];
        $tempName = $file["tmp_name"];
        $UPLOAD_FILE =  $path."/".$filename;    
        $target = $path."thumb/";
        $new_w = 41;
        $new_h = 46; 
        ini_set('memory_limit', '50M');
        if($tempName){
            //system("chmod 7777 $UPLOAD_FILE");
            if(move_uploaded_file($tempName, $UPLOAD_FILE))
            {
                $this->createthumb($filename,$path,$target,$new_w,$new_h);
                return  $filename;
            }
            else
                return false;
        }
        else{
            return false;
        }
    } 


And the last but not least saving it into database...

PHP Code:

"insert into tblfback(`fb_photo') values('$fbimg')";
$result_add  = mysql_query($sql_add);
 return true;
    } 


Please let me know if what's wrong with it.

Thanks in advance.

Individually, they are all right.
Now, what is important is how you put them together.

And what if your first step was to check that the query is executed ?
The second could be to check the return of mysql_query, to see if there was an error.

Just a pointer for the second step: mysql_error()

Thanks tripy, I'll check.

just for the info, the form is working pefectly....but not taking the image name...in database field.