Pretty basic image hosting script here:

<center><form enctype="multipart/form-data" action="<?php print preg_replace('/\/([^\/]+?)$/', '/', $_SERVER['PHP_SELF']) ?>" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="<?php print (ini_get('upload_max_filesize')>$maxsize)?ini_get('upload_max_filesize'):$maxsize; ?>" />
<center><label for="file"><img src="upload.png"><br></label><input type="file" name="file" id="file" /> <input name="submit" type="submit" value="Upload" /></center>
</form></center>
<div id="showdiv"<?php if(empty($imgurl)) { ?> style="display: none;"<?php } ?>>
<img id="showimg" src="<?php if(!empty($imgurl)) print $imgurl; else { ?>about:blank<?php } ?>" alt="Loading image..." />
</div>
<div id="squares">
</div>
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST') {
preg_match('/\.([a-zA-Z]+?)$/', $_FILES['file']['name'], $matches);
if(in_array(strtolower($matches[1]), $accepted)) {
if($_FILES['file']['size'] <= $maxsize) {
$newname = md5_file($_FILES['file']['tmp_name']).'.'.$matches[1];
move_uploaded_file($_FILES['file']['tmp_name'], $filedir.'/'.$newname);
$linkurl = 'http://'.$_SERVER['HTTP_HOST'].preg_replace('/\/([^\/]+?)$/', '/', $_SERVER['PHP_SELF']).'#'.$newname;
$imgurl = 'http://'.$_SERVER['HTTP_HOST'].preg_replace('/\/([^\/]+?)$/', '/', $_SERVER['PHP_SELF']).$filedir.'/'.$newname;
print '<h2><img src="uploaded.png"></h2> <p id="codes"><label for="codebb"></label><br />
<b><p>BB CODE:</p></b><input type="text" id="codebb" value="[IMG]'.$imgurl.'[/IMG]" onclick="javascript:this.focus();this.select();" readonly="true" /><br />
<label for="codehtml"></label><br />
<b><p>HTML CODE:</p></b><input type="text" id="codehtml" value=\'&lt;a href="'.$linkurl.'"&gt;&lt;img src="'.$imgurl.'" alt="Image hosting by '.$title.'" /&gt;&lt/a&gt;\' onclick="javascript:this.focus();this.select();" readonly="true" /><br />
<label for="codedirect"></label><br />
<b><p>DIRECT LINK:</p></b><input type="text" id="codedirect" value="'.$imgurl.'" onclick="javascript:this.focus();this.select();" readonly="true" /></p>';
} else
print '<p>Sorry, that file is too big.</p>';
} else
print '<p>Sorry, that file type is not supported.</p>';
}
?>

I would like it to display the image that was just uploaded directly after an upload, when it generates the links for said image.

The centered just uploaded image, with the BB codes and what-have-you underneath. How do I go about this?


Oh, and this script can be used at http://www.actionupload.com which I am working on.

Hi, what I would do was take the image url after it uploads, I think it was this $imgurl,

Put that in a hidden textbox, so try this inside of the form element

PHP Code:

<input type="hidden" name="imagesource" value="<?php echo $imgurl; ?>" />

and on the next page, try putting something to catch the string

PHP Code:

$test = $_POST["imagesource"]; 


and on the second page put something like

PHP Code:

<img src="<?php echo $test ?>" />

Hope this helps!

-Dillon