Test it on YOUR data.
Quote:
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Let me know if there any better string I can use for this....
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There maybe, it will depend on what you actually want to achieve.
With the information given,
SELECT columnlist FROM table WHERE column LIKE 'word%'; should work.
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A foolish consistency is the hobgoblin of little minds
Thought for today:- Is SEO the only industry where all the cowboys are Indians?
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