command php:

PHP Code:

<?php
 $referer = $_REQUEST['r']; // Referer ->
?>

<a href="category.php<? if ($r != "") { echo ""; } else { echo "?r=".$referer; } ?>"></a>

url1 example: http://www.domain.com/?r=google

if r=(google or another website) to show
<a href="category.php?r=google">Category</a>




url2 example: http://www.domain.com/?r=

if r=(nothing no website or text)
<a href="category.php">Category</a>

can someone help me with this litle command ... thanks

It seems like you were close, but you got your operator logic a little backwards (if $ir != "")

PHP Code:

<a href="category.php<?php echo (isset($_REQUEST['r']) AND !empty($_REQUEST['r'])) ? '?r=' . urlencode($_REQUEST['r']) : ''; ?>">Category</a>

You'd be better off using empty() within your condition, and an isset() check when declaring $referer .. otherwise you'll generate a PHP notice if $_REQUEST['r'] isn't set...

PHP Code:

if (isset($_REQUEST['r']))
{
    $referer = urlencode($_REQUEST['r']);
}

// then..

if (!empty($referer)) echo '?r=' . $referer; 


Edit: Sorry mgraphic didn't realise you'd included those in your example, thought you'd just corrected the logic. Though I don't think you realise empty() implicitly performs an isset() check when called, a combination of the two isn't necessary.

works thank you mgraphic !

adam89 i try your php code becouse was more easy yours but is not working ... this i did

<?php
if (isset($_REQUEST['r']))
{
$referer2 = urlencode($_REQUEST['r']);
}
if (!empty($referer2)) echo '?r=' . $referer2;
?>

and the url code:
<a href="ordernow.php<? echo $referer2; ?>"></a>

and is not working ...

if r=google is show me <a href="ordernow.phpgoogle"></a>

can you please help me with this ... this command will help me a lot thanks

Change:

PHP Code:

<?php
 $referer = $_REQUEST['r']; // Referer ->
?>

<a href="category.php<? if ($r != "") { echo ""; } else { echo "?r=".$referer; } ?>"></a>

To:

PHP Code:

<?php
if (isset($_REQUEST['r']))
{
    $referer = urlencode($_REQUEST['r']);
}
?>

<a href="category.php<?php if (!empty($referer)) echo '?r=' . $referer; ?>"></a>

works ! thank you ! you save my day and my website