Is it possible to add args to a function from an array dynamically ?

PHP Code:

<?php

$foo = array('arg1', 'arg2');

function foo()
{

echo '<pre>';
print_r(func_get_args());
echo '</pre>';

}

?>

So when the func_get_args is called, it prints

PHP Code:


Array
(
    [0] => arg1
    [1] => arg2
) 


Is this possible ?

Thanks in advance.

I don't see what you are trying to do, but as far as I know, no, you cannot.
But you can pass an array as parameter, and iterate it to extract the key/value pairs.

Its for a plugin system, the method to add plugin functions into the system has a argument for arguments to be passed into the plugins function.
I was wondering if i could put the args into an array and be passed onto the function.

I hope this has explained it ?

Then yes you can.
But you should do:

PHP Code:

<?php
function foo($pars){
  foreach($pars as $key=>$val){
    $$key=$val;  //the name in $key is created as a variable with the value "$val"
  }
}

So is not possible to use an array eg:

PHP Code:

$foo = array('arg1', 'arg2'); 


and have each of its values made into seperate function args ?

Example

PHP Code:

$foo = array('arg1', 'arg2');

// into
functionname('arg1', 'arg2');

// so if another value is added into the array it will add another arg eg

functionname('arg1', 'arg2', 'arg3'); 


Sorry if im confusing you.

No, you have to pass the array as a parameter to the function:

PHP Code:

functionName($array) 


You cannot call the function and expect it to have an array defined outside the function visible inside the function.

And in your example, arg1 and arg2 are just the elements of the array $foo.
If you call the function the way you wrote it, the arguments will always be the same.

If you would use your example, you would do

PHP Code:

$foo=array('arg1','arg2');
functionName($foo); 


Or, if you want to name your parameters:

PHP Code:

function bar($pars){
  foreach($pars as $key=>$val){
    $$key=$val;  //the name in $key is created as a variable with the value "$val"
    print("The parameter $key value is $val<br/>\n");
  }
}
$foo=array('arg1'=>'val1','arg2'=>'val2');
bar($foo); 


So no, you cannot use func_get_args(), you must iterate through the array given in parameter, like I showed you previously.

Which gives me:

$:> php 3.php
The parameter arg1 value is val1<br/>
The parameter arg2 value is val2<br/>
$:>_

Thanks tripy for all your help (:

I might be misunderstanding something, but take a look at this code and see if it helps you in understanding things in more depth:

PHP Code:

<?php
function myPlugin() {
  $arguments_passed = func_get_args();
  foreach($arguments_passed as $an_argument) {
    if (is_array($an_argument)) {
      echo '<pre>', print_r($an_argument, true), '</pre>';
    } else {
      echo $an_argument,'<br>';
    }
  }
}
myPlugin('1st parameter');
echo '<hr><br>';
myPlugin('1st parameter', '2nd parameter', 85);
echo '<hr><br>';
myPlugin(array('Item 1','Item 2','Item 3'));
echo '<hr><br>';
myPlugin(array('A'=>'Item 1','B'=>'Item 2','C'=>'Item 3'));
?>