PHP Forum

**canadian_angel** · 03:18 PM

Hi, This code for some reason is producing a syntax error from this line:
foreach ($types = 0; $types < 4; $types++) and i can't figure out why. Can anyone help? Please!

PHP Code:


			
<?php // Script  10.6 - create-four-cell-table
     // This script creates a four cell  table.

   // Address error handling.
   ini_set  ('display_errors', 1);
   error_reporting (E_ALL & ~E_NOTICE);
function  tea ($types){
$types = array ("Chinese Green", "Japanese Red",  "Korean Black", "British White");
foreach ($types = 0; $types < 4;  $types++) {
echo "<tr><td> ". $types ."
</tr></td>";
}
}
?>
<!DOCTYPE  HTML PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-Transitional.dtd">
<html  xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta  http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<title>Teas  of the World!</title>
</head>
<body>
<table>
<?php  echo tea()?>
</table>
</body>
</html>

**chrishirst** · 06-30-2010, 03:25 PM

PHP Arrays are 0 based so your array is 0 .. 3 NOT 0 .. 4

You also have the wrong syntax for a foreach loop.

**NullPointer** · 06-30-2010, 07:38 PM

Why does the function tea take the parameter $types, but then set it to a new value?

As Chris pointed out, you are using for loop syntax with a foreach loop. Try:

PHP Code:


			
foreach($types as $t)

{

     echo "<tr><td> ". $t ."</tr></td>";

}

or

PHP Code:


			
for($i = 0; $i < count($types); $i++)

{

     echo "<tr><td> ". $types[$i] ."</tr></td>";

}

Also, you forgot your ; on this line:

PHP Code:


			
<?php  echo tea()?>