Hey guys,

I was wondering if it is possible to find a string in an array. Such as this:

PHP Code:

$imgFileExt = array(".png",".jpg",".jpeg",".svg",".ico",".gif");//array full of image file extensions
$imgCheck = array_values($imgFileExt);//get the array's values
if (preg_match("/$imgCheck/i", $fileTR)) { //checks if there's a match with the array values and the file to read
          echo "This file is an image";//if there is, tell the user it's an image
} 


Basically I want to find if the file ($fileTR) contains '.png','gif','jpeg'.......etc. But it's not working

What am I doing wrong?

Thanks

-PG

in_array

Yeah I tried that... It didn't work...

I'll try again, maybe I did something funky.

Ah, it turns out I did do something funky. I don't know what, so I just rewrote the thing from scratch and now it works Thanks!

The function array_values returns all of the values (not keys) in an array. Calling it on a non-associative array (as you are doing here) won't have any affect; the input is the same as the output.

Since $imgCheck is an array the line:

PHP Code:

if (preg_match("/$imgCheck/i", $fileTR)) 


will not work as intended.

The way I would do this would be to get the extension from the file name, then check if it is in the array:

PHP Code:

$imgFileExt = array(".png",".jpg",".jpeg",".svg",".ico",".gif");
$expr = '/\.([^\.]+)$/';

$match;
preg_match($expr, $fileTR, $match);
if(in_array($match[0], $imgFileExt))
{
    echo 'image';
} 


Yeah, that's what I did Thanks

My version:

PHP Code:

          $imgFileExt = array(".png",".jpg",".jpeg",".svg",".ico",".gif","x.png"); 
          $ext = substr(strrchr($fileTR, '.'), 1);
if (in_array(".$ext", $imgFileExt)) {
          echo "<b><img src='$directory$fileTR' height='30px' width='30px' style='margin-right:40px;' />$DispFormat<a href='$directory$fileTR'>".strtr(preg_replace("([A-Z]+)", " $0", $fileTR),$ridOfFExt)."</a>$DispFormat2</b><br />";
        } 


Yep, it's a thumbnail viewer