I'm having a slight problem setting an img tag in a variable. This variable will be called later in the page.

PHP Code:

$avatar = $uploadrow['avatar'];
$avatarshow = "<img src=\'/avatars/$avatar\' width=\'100\' height=\'100\'>"; 


Now I am certain the problem is with my syntax in the avatarshow variable. I tested it by typing out the full name of the file, and it is shown just fine. But doing it this way causes problems. Any suggestions on fixing this code?

(I'm not getting any mysql errors)

You can try:

PHP Code:

$avatarshow = '<img src="avatars/' . $avatar . '" width="100" height="100" />'; 


Originally Posted by Smudly

I'm having a slight problem setting an img tag in a variable. This variable will be called later in the page.

PHP Code:

$avatar = $uploadrow['avatar'];
$avatarshow = "<img src=\'/avatars/$avatar\' width=\'100\' height=\'100\'>"; 


When writing a string in double-quotes, you don't need to escape single-quotes ('), but you do need to escape other double-quotes (")