hello am new to php + mysql, I am not able to connect php with my sql's giving him an error in mysql_fetch_array, I'm very new even if they could help me I would greatly appreciate it, the site is this www.creddinh.com.br/dinh, now I thank everybody, here's the piece of code.

while($v=mysql_fetch_array($bB,MYSQL_ASSOC)){
$_CATEG["$v[id]"] = $v[nome];
}
$bB=mysql_query("SELECT * FROM {$DB_PRENOM}_subcategorias ORDER BY idcateg, nome");
while($v=mysql_fetch_array($bB,MYSQL_ASSOC)){
$_SUBCATEG["$v[id]"] = $_CATEG[$v[idcateg]].' - '.$v[nome];
}

and here the line 53

Array('campo'=>'subcategoria', 'nome'=>'Sub Categorias', 'tamanho'=>'200', 'tipo'=>'select', 'tamanho'=>'30', 'opcoes'=>Array(''=>'')+$_SUBCATEG, 'traduzivel'=>'falso'),

the query returned no records

Now I added

$bB=mysql_query("SELECT * FROM {$DB_PRENOM}_subcategorias ORDER BY idcateg, nome")or die( mysql_error() );

some mistakes but i went ta still giving an error on line 16

tracking site www.creddinh.com.br/dinh

I thank you all

I am Brazilian do not speak English well maybe that might hinder me T_T

Table 'cred_banco.Creddinh_subcategorias' doesn't exist

Should give you a clue to the error

how do you solve x_x I'm pretty new to php and mysql, is how you explain? please.

using the correct name for the table you are tring to access would fix it.

I could connect many thanks.

very thank you

hey it helps me too