hello there, this is my command

PHP Code:

<?php

 $allowed_refferer = array(
  'http://www.google.com',
  'http://www.yahoo.com'
 );

 if (in_array($_SERVER['HTTP_REFERER'], $allowed_refferer)) {
  echo 'a';
 } else {
  echo 'b';
 }

?>

i have one problem hope someone can help me with this...
if the refferer is http://www.google.com is show me echo a

but if the refferer is http://www.google.com/search... is not working anymore ... how i can make this work ?

i want to use array becouse is more easy to add the links becouse before i use preg_match ...

Soooo basically you want a PHP script that will say something like "Hello Googler" if the user came to your site off of a Google search?

In that case, I'll try to have something working for you shortly.

Taken from php.net's $SERVER page:

Originally Posted by PHP.net

The address of the page (if any) which referred the user agent to the current page. This is set by the user agent. Not all user agents will set this, and some provide the ability to modify HTTP_REFERER as a feature. In short, it cannot really be trusted.

K done, it searches for a name, so just put anything in there where 'google' is and it'll find it.

PHP Code:

<?php

function is_ref_legal($ref) {
  return preg_match("/google/i",$ref);
}

 if (is_ref_legal($_SERVER['HTTP_REFERER'])=="1") {
  echo 'a'; //Was found
 } else {
  echo 'b'; //Was not found
 }
?>

Keep in mind that if you want to add a slash (/) to the preg_match (example: directory/subdirectory) into (directory\/subdirectory), because a slash will end the preg_match.

Try this...

PHP Code:

 
$allowed_refferer = array(
  'google',
  'yahoo'
 );
 
$refer = explode('.',$_SERVER['HTTP_REFERER']);
 if (in_array($refer[1], $allowed_refferer)) {
  echo 'a';
 } else {
  echo 'b';
 } 


Ah, phpdasan's solution is better, go with his

Hm.. what about www . google . notreallygoogle . com. Maybe instead of using the second element, use the second to last element.

So use $refer[count($refer)-2] instead of $refer[1]

<?php
// Create a simple array.
$array = array(1, 2, 3, 4, 5);
print_r($array);

// Now delete every item, but leave the array itself intact:
foreach ($array as $i => $value) {
unset($array[$i]);
}
print_r($array);

// Append an item (note that the new key is 5, instead of 0).
$array[] = 6;
print_r($array);

// Re-index:
$array = array_values($array);
$array[] = 7;
print_r($array);
?>

These things might be helpful to you.

GetGamesHere's solution would accept google and yahoo in the US as referrers, but not their sites in other countries; e.g. google.com.au or yahoo.co.uk
phpdasan's would accept these other sites, but has the problem GetGamesHere raised.

If either of these are fine for your site, then go with whichever meets your needs, but if you want to accept international referrals AND block fake referrals the condition gets a bit more complex

PHP Code:

$allowed_refferer = array(
 'google',
 'yahoo'
);
 
$refer = explode('.',$_SERVER['HTTP_REFERER']);
if (((in_array($refer[count($refer)-2], $allowed_refferer)) && (in_array($refer[count($refer)-1], 'com'))) || ((in_array($refer[count($refer)-3], $allowed_refferer)) && ((in_array($refer[count($refer)-2], 'com')) || (in_array($refer[count($refer)-2], 'co'))))) {
echo 'a';
}
else {
echo 'b';
} 


Should do it (I think I've got all the brackets in the right places )