Hey guys im new to php i dont really dont know much i dont know if what i did is possible or not but im getting and undefined variable error here does anyone know why? please help... here is the code

the variable undefined is $crem_vel

PHP Code:

$tipo = $fif['Tipo de Servicio'];
if ($tipo == "Cremacion con Velacion")
{
    $crem_vel = "Cremacion con Velacion";
}
else if ($tipo == "Cremacion Directa")
{
    $crem_dir = "Cremacion Directa";
}
else if ($tipo == "Sepultura con Velacion")
{
    $sep_vel = "Sepultura con Velacion";
}
else if ($tipo == "Sepultura Directa")
{
    $sep_dir = "Sepultura Directa";
}
else if ($tipo == "Traslado Guadalajara/Mexico DF")
{
    $tras_df = "Traslado Guadalajara/Mexico DF";
}
else if ($tipo == "Traslado Guatemala")
{
    $tras_gua = "Traslado Guatemala";
}
else if ($tipo == "Traslado Salvador/Honduras/Nicaragua")
{
    $tras_sal = "Traslado Salvador/Honduras/Nicaragua";
}
else 
{
    $crem_vel = $crem_dir = $sep_vel = $sep_dir = $tras_df = $tras_gua = $tras_sal = "";
} 


Thanks

Its a notice not an error. It means you're making a reference to $crem_vel, but it has not been declared. I don't see any references to $crem_vel in the code you provided, only assignments. Most likely what's happening is the script isn't executing the portion of the if statement where $crem_vel is assigned.

You should know that a script can function perfectly fine while still issuing notices; they're useful for debugging but can often be ignored. In a production environment you should at least set error reporting to E_ALL & ~E_NOTICE (everything but notices) if not disable errors messages all together (ie set display_errors to off).

it shows it as an error, it doesnt run the rest of the script, the output is for a pdf form, im getting the data from the database, this is what i do the field is a checkbox list with 6 items, but for some reason this is the way it works i have to do a statement for each variable. just though it would work the other way, using just one statement for all the variables..

Thanks for the reply

PHP Code:

$tipo = $fif['Tipo de Servicio'];
if ($tipo == "Cremacion con Velacion")
{
    $crem_vel = "Cremacion con Velacion";
}
else
{
    $crem_vel = "";
}

$tipo1 = $fif['Tipo de Servicio'];
if ($tipo1 == "Cremacion Directa")
{
    $crem_dir = "Cremacion Directa";
}
else 
{
    $crem_dir = "";
} 
  
$fdf_data_strings = ('crem_vel' => $crem_vel, 'crem_dir' => $crem_dir); 


.......

Try initializing your variables at the top of the script and then changing them only if needed. For example,

PHP Code:

$crem_vel = $crem_dir = "";
$tipo = $tipo1 = $fif['Tipo de Servicio'];
if ($tipo == "Cremacion con Velacion")
{
    $crem_vel = "Cremacion con Velacion";
}
if ($tipo1 == "Cremacion Directa")
{
    $crem_dir = "Cremacion Directa";
} 


Also, from the PHP site:

Originally Posted by http://us2.php.net/manual/en/language.variables.basics.php

It is not necessary to initialize variables in PHP however it is a very good practice.

Thank you very much!!! It worked great!!!