Hello there, this is my script hope someone can fix this for me ...

PHP Code:

<?php

$allow = array(
    'http://www.google',
    'http://search.yahoo.com'
);

 if (in_array($_SERVER['REMOTE_ADDR'], "~$allowed_ips~i")) {
  echo "a";
 } else {
  echo "b";
 }

?>

Right now im using this command

PHP Code:

if (strpos($_SERVER["HTTP_REFERER"], "http://www.google")) { "a"; } 


But hope someone can help me to make this, to read from array so can be more easy for me to add the websites what i need

Thank you !

You can't use preg_match with array but you can use implode before matching instead.

PHP Code:

<?php

$allow = array(
    'http://www.google',
    'http://search.yahoo.com'
);

$combined_array = implode(',',$allow);

if (strpos($_SERVER["HTTP_REFERER"], $combined_array)) { "a"; } 

?>

i try like this

PHP Code:

<?php

$allow = array(
    'a',
    'b'
);

$combined_array = implode(',',$allow);

if (strpos('asd', $combined_array)) { "a"; } 

?>

normaly was need to show me ( a ) but is not show, can you please tell me how i can fix this, thank you

use echo "a" instead of just "a"

i try but didnt work for me

What does the script look like now?