I am bulding a site where users can click on links to download information about our software. When they click on a link it takes them to a page where they enter contact infor, press submit, and get the file, all using php.

When you click through it prints the filename you are downloading using php. There are a variety of file types - pps, pdf and html. My boss would like the pdf icon to appear when you download a pdf.

at the minute where this appears I have the following code:

<?php echo $file ?>
<?php if (preg_match('/\.pdf$/i', $file)) {show_source ("http://www.codestone.net/gfx/adobePDF.gif");} ?>


this is working in as much as when it is a pdf file, the image's path is printed, but I do not know what command to use to make it actually show the image instead of showing it's path.

What should I write instead of 'PRINT' to show the image?

thanks for any tips x

use PHP to assemble an <IMG> tag with the pathname within it.

<?php echo "<img src=\"".$file."\" border=\"0\">"; ?>
<?php if (preg_match('/\.pdf$/i', $file)) {show_source ("http://www.codestone.net/gfx/adobePDF.gif");} ?>

Is that what you mean?

Errr.. doesn't that put the .pdf into the img tag?
You need to get the .gif file into an img tag if you want it to show up in the browser. What are you using show_source() for in this case?

Thats what I thought - what are you trying to achieve with your code? "if the file name has ".pdf" in it, view the source of the adobePDF.gif?"

Can't understand why your using show_source()...

Thanks for your help guys it turned out to be a really silly error I made,

I actually made a mistake with my first post - I tried show_source and it didn't work at all, and I went back to trying print instead but pasted the wrong code in my post!

any how, I just needed to put it as an image tag like so:

{print ("<img src=http://www.codestone.net/gfx/adobePDF.gif>");}

thanks for your replies though!