i need to know this fairly quickly so if anyone could help me i would very very appreciative

ok i have this string in php

START
New York
END
START
London
END
START
Sydney
END
START
Tokyo
END

i need a short php script that involves regex that goes through that string and returns an array something similar to

PHP Code:

[0] => "New York"
[1] => "London"
[2] => "Sydney"
[3] => "Tokyo" 


i will be very thankful to whoever can help me out

PHP Code:

<?

$string = "START
New York
END
START
London
END
START
Sydney
END
START
Tokyo
END";

$re = "!START\r?\n?(.*?)\r?\n?END!";
preg_match_all($re, $string, $match);
$cities = $match[1];

?>

Goes?

thankyou, ill begin testing soon

is this possible too?

have this string

START (CITY1)
New York
END
START (BLABLA)
London
END
START (CITY3)
Sydney
END
START (GOOGLEROX)
Tokyo
END

and it return this??::!::

PHP Code:

["CITY1"] => "New York"
["BLABLA"] => "London"
["CITY3"] => "Sydney"
["GOOGLEROX"] => "Tokyo" 


It should work, because I run it before posting and it worked fine. But depending on what is your OS you may replace \r?\n? to simply \n (on Unix-like) or \r on Mac or \r\n on Windoze.

i dont have a problem with the original post

but i just want too see whether or not the second post is also possible... the one with Strings for keys in the array

Done again

PHP Code:

<?
$string="START (CITY1)
New York
END
START (BLABLA)
London
END
START (CITY3)
Sydney
END
START (GOOGLEROX)
Tokyo
END";

$re = "!START \(([^\)]+)\)\r?\n?(.*?)\r?\n?END!";
preg_match_all($re, $string, $match, PREG_SET_ORDER);

foreach ($match as $m) {
    $arr[$m[1]] = $m[2];
}

print_r($arr);
?>

Output:
C:\www\swdl>php zzz.php
Array
(
[CITY1] => New York
[BLABLA] => London
[CITY3] => Sydney
[GOOGLEROX] => Tokyo
)

What is it all for?

ive made the sample city string fairly easy to understand so i dont have to explain what im doing but i am making the skin portion of a forum system i am contructing. The forum will be very powerful in the end and i just needed to get over this tiny hurdle. many thanks to you mtishetsky

i am always welcoming people to help develop this so if u are interested then well just shout