I'm having problems in listing the contents of my database.

Here's the error I get.

Error type: 2
Error description: mysql_query(): supplied argument is not a valid MySQL-Link resource
Error file: /include/dbconnection.php
Error line: 26

First 33 Lines of Code for dbconnection.php

PHP Code:

<?php

function db_connect() 
{
    global $host,$user,$pwd,$errstr,$sys_dbname,$port;
    $strhost=$host;
    if($port && $port!=3306)
        $strhost=$strhost.":".$port;

$conn = mysql_connect ("localhost", "feud42c_james", "vallis") or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("feud42c_mort");
    if (!$conn|| !mysql_select_db($sys_dbname,$conn)) 
    {
      trigger_error(mysql_error(), E_USER_ERROR);
    }
    return $conn;
}

function db_close($conn)
{
  return mysql_close($conn);
}

function db_query($qstring,$conn) 
{
    if(!($ret=mysql_query($qstring,$conn)))
    {
      trigger_error(mysql_error(), E_USER_ERROR);
    }
    return $ret;

Can anyone help ? Many thanks

Did you forget to call db_connect() before calling db_query()? Also do you get $conn from db_connect() and pass it correctly to db_query() or just call db_connect() without passing the return?

i guess u didn't try to include your DB..

<? php
include ("dbconnect.php"); ---------------> at the very top and again ur query is wrong

i guess u didn't try to include your DB..

<? php
include ("dbconnection.php"); ---------------> at the very top and again ur query is wrong