PHP Forum

**The_Anomaly** · 06-24-2005, 06:45 PM

I'm reading a tutorial in a book on how to make a basic calander, I wrote exactly how they have it but i keep getting these 2 lines on the top of my page that say:

Notice: Undefined index: month in c:\program files\easyphp1-8\www\mycoding\listing22.php on line 3

Notice: Undefined index: year in c:\program files\easyphp1-8\www\mycoding\listing22.php on line 3

I this it might be because of this EasyPHP that i'm running but i wanted to see if someone else got the same errors using a real install.

Everything comes on the page as its supposed to just with those messages.

Code:

<?php
define("ADAY" , (60*60*24));
if (!checkdate($_POST['month'], 1, $_POST['year']))  {
	$nowArray = getdate();
	$month = $nowArray['mon'];
	$year = $nowArray['year'];
}else {
	$month = $_POST['month'];	
	$year = $_POST['year'];
}
$start = mktime (12, 0, 0, $month, 1, $year);
$firstDayArray = getdate($start);
?>


<!-- =====================================starting html form =========================-->

<html>
<head>
	<title><?php echo" Calendar: " .$firstDayArray['month'] ." ".$firstDayArray['year'] ?></title>
<head>
<body> 
<!-- =====================================Month Dropdown Menu =========================-->
<form method="post" action="<?php echo "$_SERVER[PHP_SELF]"; ?>">
<select name="month">
<?php
$months = Array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
for ($x = 1; $x <= count($months); $x++)	{
	echo "<option value=\"$x\" ";
	if ($x == $month){
	echo " SELECTED";
	}
	echo ">".$months[$x-1]. " ";
}
?>
</select>
<!-- =====================================Year Dropdown Menu =========================-->
<select name="year">
<?php
for ($x=1980; $x<=2010; $x++)	{
	echo "<option";
	if($x == $year) {
		echo "SELECTED";
		}
	echo ">$x";
}
?>
</select>
<input type="submit" value="Go!">
</form>
<br>
<!-- =====================================Calander =========================-->
<?php
  $days = Array("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat");
  echo "<TABLE BORDER=1 CELLPADDING=5<tr>\n";
	foreach ($days as $day)
	{
		echo "<TD BGCOLOR=\#CCCCCC\" ALIGN=CENTER><strong>$day</strong></td>\n";
	}
for ($count=0; $count < (6*7); $count++)
{
	$dayArray = getdate($start);
		if (($count%7) == 0) 
	{
			if ($dayArray['mon'] != $month)
		   {
			break;
		   } 
		else 
		   {
		echo "</tr><tr>\n";
	        	    }
	}
	if ($count < $firstDayArray['wday'] || $dayArray['mon'] != $month) 
		     {
		echo "<td>&nbsp;</td>\n";
		     } 
		else 
		        {
		  echo "<td>".$dayArray['mday']." &nbsp;&nbsp</td>\n";
		  $start +=ADAY;
		           }
}
echo "</tr></table>";
?>
 
</body>
</html>

**metho** · 06-24-2005, 06:52 PM

Notices should only come up on a development server. Lazy coders will ignore references which they know will throw a notice. This is especially problematic when the script includes a header redirect as it simply wont work. Notices can also disrupt CSS loading correctly in some cases.

If you want the notices to disappear, change the if condition to:

Code:

if(isset($_POST['month']) && isset($_POST['year'])){
if (!checkdate($_POST['month'], 1, $_POST['year']))  {
	$nowArray = getdate();
	$month = $nowArray['mon'];
	$year = $nowArray['year'];
}else {
	$month = $_POST['month'];	
	$year = $_POST['year'];
}
}

**The_Anomaly** · 09:55 PM

I just wanted to make sure the notices wouldnt show up if i was coding something and threw it up on a server. If i understand you correctly if i coded something and had those errors using easyPHP then took the same thing and threw it up on a server the people going to that site would not be able to see the notices.

I also notice something weird is happening in the year drop down. 2004 and 2005 are stuck together and displays as 20042005. any idea's what that could be from?