Will this script work:

PHP Code:

<?php  
/* written: 3-31-05 */  
session_start(); 
session_id();
//get the username and password from the session, almost like magic!  
$password = $_SESSION['password'];  
$username = $_SESSION['username'];  
//connect to DB, you may need to change settings  
mysql_connect("localhost", "username", "password") or die(mysql_error());  
mysql_select_db("table") or die(mysql_error());  
$res = mysql_query("SELECT * FROM logsys WHERE username='$username' AND password='$password'") or die(mysql_error());  
if(mysql_num_rows($res) == 1)  
{  
while($get=mysql_fetch_array($res))
$Buildingneeded1 = 5
if($get[building1] < Buildingneeded1){ 
echo " ";
}
else{ 
  echo
  "<form action="BuyBuildings.php" method="post">
<p>HQ <? 
while($get=mysql_fetch_array($res))
echo(" ( Current level<b> " . $get[building1] . "</b> )");?> </p>
<p>The HQ is where the main stuff in your base  happens.</p>
<table>
<tr>
<td>Money: 50 Food: 50 Wood: 50 Power: 50 </td>
<td><input name="building1" type="hidden" value="1" /></td>
</tr>
</table>
<input type="submit" name="submit" value="Buy" />
</form>";
<?else  
//hmmm we didnt find there data? error time! :eek:  
{  
echo("<center><font face=\"Verdana\">Sorry, your not logged in, proceed <a href=\"login.php\">here</a> to login.");  
}  
?>

What i want it to do is only display the form if the building in the database is above level 5. Now would this script work?

Wy don't you try it?

I did and it didn't work

Doesn't work in what sense?
Doesn't do what you want, or gives errors?

This line
$Buildingneeded1 = 5
Looks like its missing a ; at the end... it should be like
$Buildingneeded1 = "5";

I did what you said and the error i get is:

Parse error: parse error, unexpected T_STRING, expecting ',' or ';' in /home/robsdabe/public_html/levels.php on line 23

I just had a proper look through your code and it's all over the place.
You ave php starting and ending at random places and " where they are not allowed.

PHP Code:

<?php  
/* written: 3-31-05 */  
session_start(); 
session_id();

//get the username and password from the session, almost like magic!  
$password = $_SESSION['password'];  
$username = $_SESSION['username'];  
//connect to DB, you may need to change settings  


mysql_connect("localhost", "username", "password") or die(mysql_error());  
mysql_select_db("table") or die(mysql_error());  
$res = mysql_query("SELECT * FROM logsys WHERE username='$username' AND password='$password'") or die(mysql_error());  
if(mysql_num_rows($res) == 1)  
{  
while($get=mysql_fetch_array($res))
$Buildingneeded1 = "5";
if($get[building1] < Buildingneeded1)
{ 
echo " ";
}
else
{ 
 echo '<form action="BuyBuildings.php" method="post">
<p>HQ'; 
 
while($get=mysql_fetch_array($res))
echo ' ( Current level<b> " . $get[building1] . "</b> )
 
</p>
<p>The HQ is where the main stuff in your base  happens.</p>
<table>
<tr>
<td>Money: 50 Food: 50 Wood: 50 Power: 50 </td>
<td><input name="building1" type="hidden" value="1" /></td>
</tr>
</table>
<input type="submit" name="submit" value="Buy" />
</form>';

}

else  
//hmmm we didnt find there data? error time! :eek:  
{  
echo '<center><font face=\"Verdana\">Sorry, your not logged in, proceed <a href=\"login.php\">here</a> to login.';  
}  
?>

Try that..

Ok cheers, tried it and now i get:

Parse error: parse error, unexpected T_ELSE in /home/robsdabe/public_html/levels.php on line 44

You don't need to escape your quotes in the last echo line.

PHP Code:

echo '<center><font face="Verdana">Sorry, your not logged in, proceed <a href="login.php">here</a> to login.';