Is it possible to compare to multiple values in a single boolean statement?

For example, I have a CSV file which contains about 60 lines of information. I have read the file and saved the information into a multi dimensional array which is accessible as $arr_info[$row][$cell]. Now I want to access just rows 0,2,46-56.

I was trying to do it in a loop (this is contained in a while loop with a counter $cnt):

  if($cnt == (0 | 2 | 46 | 47 | 48 | 49 | 50 | 51 | 52 | 53 | 54)) { 
      echo $arr_info[$cnt][1]."<br>";
}

I know that the information is in the array because I can echo the whole array without a problem.. However, I'm trying to have just one boolean operator statement (if) that covers all values considering the code that is being executed is the same.

My code isn't working... Can anyone help out!

You can try in_array() function.

Originally Posted by zincoxide

  if($cnt == (0 | 2 | 46 | 47 | 48 | 49 | 50 | 51 | 52 | 53 | 54)) { 
      echo $arr_info[$cnt][1]."<br>";
}

What you've got there is a bitwise or, not a boolean or. A bitwise or takes the binary representation of one operand and then ORs each bit with the binary representation of the other. Thus 12 | 5 = 13 since 12 is 1100 in binary and 5 is 0101. ORing each bit gives 1101 = 13.

To change the code to do a boolean OR, you would need to re-write it as follows:

PHP Code:

  if($cnt == 0 || $cnt == 2 || $cnt ==  46 || $cnt == 47 || $cnt ==  48 || $cnt ==  49 || $cnt ==  50 || $cnt ==  51 || $cnt ==  52 || $cnt ==  53 || $cnt ==  54)) { 
      echo $arr_info[$cnt][1]."<br>";
} 


Note that a boolean OR is || not |

Of course this is very long winded and it would be much better to do something like

PHP Code:

if( ($cnt >= 46 && $cnt <= 54) || $cnt == 0 || $cnt == 2) {
 echo $arr_info[$cnt][1]."<br>";
} 


Thanks.

or use a switch statement

PHP Code:

switch ($cnt)
{
 case '0','2','46','47','48','49','50','51',' 52','53','54':
      echo $arr_info[$cnt][1]."<br>";
      break;
 defulat:
     break;
}