PHP Code:

if ($feed->get_feed_link()) echo "<a href=\"javascript:hideshow(document.getElementById('adiv'))\">" echo $feed->get_feed_title(); if ($feed->get_feed_link()) echo '</a>'; ?> 


can someone correct the link for me
i cant figure out how to get it to work


heres the javascript

PHP Code:

<script type="text/javascript">
function hideshow(which){
if (!document.getElementById)
return
if (which.style.display=="block")
which.style.display="none"
else
which.style.display="block"
}
</script> 


when you click the link, it shows the div id with the css code: display: block

i get this error
Parse error: parse error, unexpected T_ECHO, expecting ',' or ';' in C:\xampplite\htdocs\rss\test\test.php on line 25

Originally Posted by raptrex

PHP Code:

if ($feed->get_feed_link()) echo "<a href=\"javascript:hideshow(document.getElementById('adiv'))\">" echo $feed->get_feed_title(); if ($feed->get_feed_link()) echo '</a>'; ?> 


You can only have one echo per statement:

PHP Code:

$feed_title = $feed->get_feed_title();

if($feed->get_feed_link()) {
  echo "<a href=\"javascript:hideshow(document.getElementById('adiv'))\">$feed_title</a>"; 


I'm not sure what you are trying to do there... Why do you have an if statement to echo "</a>"??

Anyways, you can see what I did there... You were using echo twice, but you can only use it once per line.